[コンプリート！] (x^2 y^2 x)dx xydy=0 747356-6. (x^(2)-y^(2))dx-xydy=0

 Ex 95, 6 Show that the given differential equation is homogeneous and solve each of them 𝑥 𝑑𝑦−𝑦 𝑑𝑥=√(𝑥^2𝑦^2 ) 𝑑𝑥 Step 1 Find 𝑑𝑦/𝑑𝑥 x dy − y dx = √(𝑥^2𝑦^2 ) dx x dy = √(𝑥^2𝑦^2 ) dx y dx x dy = (√(𝑥^2𝑦^2 )𝑦) dx 𝑑𝑦/𝑑𝑥 = (√(𝑥^2 𝑦^2 ) 𝑦)/𝑥 Step 2 Put 𝑑𝑦/𝑑𝑥 =A curve through (1, 0) and satisfying the differential equation (1 y2)dx xy dy = 0 is (A) a circle (B) a parabola an ellipse (D) a hyperbola 详细过程请见下图,希望对亲有帮助 (看不到图的话请Hi我) 希望对亲有帮助 围成D的三条直线分别是 AB：y = x/2 1/2 BC：y = 3x

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6. (x^(2)-y^(2))dx-xydy=0

6. (x^(2)-y^(2))dx-xydy=0- (x²xyy²)dxxydy=0 answer with solution asistinsilverlp8ut9y is waiting for your help Add your answer and earn pointsD/dx x^2 y^4, d/dy x^2 y^4 WolframAlpha Have a question about using WolframAlpha?

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(y^22xy)dx (x^2) dy = 0 Integrating factor y^2 solution xx^2/y = C Finding the integrating factor Giving these things some names names M(x,y) = y^22xy N(x,y) = x^2 M(x,y) dx N(x,y) = 0 We're looking to make this an exact equation, because if we do, it can be solved rather systematically In order to be exact, by claurait's theoem (think that's the name ofAvail 25% off on study pack Avail OfferApply suitable substitution, solve these equations by separation variable method (i) (x 22 y 2) dx xydy = 0 (ii) x 2 y 03 xy2 y 2 = 0 (iii) y 2 x 2 dy dx = xy dy dx (iv) (x y) dy = (yx) dx (v) x sin(y x) dy dx = y sin(y x) x (vi) x 3 dy dx = y 3 y 2 p y 2x 2 (vii) 2 y exp(x/y) dx (y2 x exp(x/y)) dy = 0 (viii) (x exp(y/x)y

Learn how to solve differential equations problems step by step online Solve the differential equation xy*dx(1x^2)dy=0 Grouping the terms of the differential equation Group the terms of the differential equation Move the terms of the y variable to the left side, and the terms of the x variable to the right side Simplify the expression \frac{1}{y}dy Integrate both sides of theSolution for 2 (2x^2y^2)dx (xy)dy=0 equation Simplifying 2 (2x 2 y 2) * dx 1 (xy) * dy = 0 Reorder the terms for easier multiplication 2dx (2x 2 y 2) 1 (xy) * dy = 0 (2x 2 * 2dx y 2 * 2dx) 1 (xy) * dy = 0 Reorder the terms (2dxy 2 4dx 3) 1 (xy) * dy = 0 (2dxy 2 4dx 3) 1 (xy) * dy = 0 Multiply xy * dy 2dxy 2 4dx 3 1dxy 2 = 0 Reorder the terms 2dxy 2 1dxy 2The line y = mx 1 is a tangent to the curve y2 = 4x Find the

 Solve (x^2y^2x)dxxy dy =0 Get the answers you need, now! Ex 95, 4 show that the given differential equation is homogeneous and solve each of them (𝑥^2−𝑦^2 )𝑑𝑥2𝑥𝑦 𝑑𝑦=0 Step 1 Find 𝑑𝑦/𝑑𝑥 (𝑥^2−𝑦^2 )𝑑𝑥2𝑥𝑦 𝑑𝑦=0 2xy dy = − (𝑥^2−𝑦^2 ) dx 2xy dy = (𝑦^2−𝑥^2 ) dx 𝑑𝑦/𝑑𝑥 = (𝑦^2 − 𝑥^2)/2𝑥𝑦 Step 2 Putting F(x, y) = 𝑑𝑦/𝑑𝑥 and finding F (xsqrt (x ^ (2) y ^ (2)) y ^ (2)) dx xydy = 0 সমাধান Updated On 72 To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!

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 The general solution of the differential equation √(1 x^2 y^2 x^2y^2) xy(dy/dx) = 0 is (where C is a constant of integration)For the equation (x^2 y^2 x)dx xydy =0 , take xy=V(x) Obtain ( x^2 V^2/x^2 x )dx V( xdV Vdx)/x^2 =0 Then (x^2 x)dx VdV/x =0Separating (x^3 x^2)dx = VdV Integrating obtain the solution 6x^2y^2 4x^3 3x^4 = C I Solve the following problem (please show the whole procedure) Show transcribed image text Expert Answer Who are the experts?

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 Solve x(√(x²y²)) y²dx xydy=0 Share with your friends Share 1 x x 2 y 2y 2 dx xy dy = 0 x x 2 y 2y 2 dx =xy dy dyNext Previous Related Questions Solve the following equations calculate y^''' for y=e^x/x If , then for what value of a is A an identity matrix? solve y^3 dx2 (x^3xy^2) dy=0 asked in PRECALCULUS by anonymous differentiation if y = (3x^3) (e^ (2x))/ Inx Find d^2y/dx^2 asked in CALCULUS by linda Scholar derivatives usingchainrule

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Watch Video in App This browser does not support the video element 412 k 358 k Answer Given, √(1x 2 y 2 x 2 y 2) xydy/dx=0 By simplifying the equation, we get Now substituting these value of t and m, we get Question 21 x√(x 2 y 2) – y 2dx xydy = 0 Solution We have, x√(x 2 y 2) – y 2dx xydy = 0 dy/dx = x√(x 2 y 2) – y 2/xy dy/dx = y 2 – x√(x 2 y 2)/xy It is a homogeneous equation, So, put y = vx (i) On differentiating both sides wrt x, dy/dx = v x(dv/dx) So, v x(dv/dx) = v 2 x 2 – x√(x 2 v 2 x

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 The GS is y^2 = (A x^4)/(2x^2) Or, alternatively y = sqrt(A x^4)/(sqrt(2)x) We have (x^2 y^2) \ dx xy \ dy = 0 Which we can write in standard form as dy/dx = (x^2 y^2)/(xy) 1 Which is a nonseparable First Order Ordinary Differential Equation`therefore x^2 y^2 = cx`, where c is constant which is the required general solution Concept Methods of Solving First Order, First Degree Differential EquationsDescribe the Transformation y=3(x2)^21 The parent function is the simplest form of the type of function given Simplify Tap for more steps Simplify each term Tap for more steps Rewrite as Expand using the FOIL Method Tap for more steps Apply the distributive property

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Incoming Term: (x^2+y^2+x)dx+xydy=0, solve (x^2+y^2+x)dx+xydy=0, (x^2+y^2)dx+(x^2-xy)dy=0 homogeneous, (x^2+y^2)dx-xydy=0 integrating factor, solve (x^2+y^2)dx+(x^2-xy)dy=0, (1+x^2+y^2+x^2y^2)dx+xydy=0, (x^2-xy+y^2)dx-xydy=0, 6. (x^(2)-y^(2))dx-xydy=0, solve (x sqrt(x^(2)+y^(2))-y^(2))dx+xydy=0, the possible integrating factor of (x^(2)+y^(2)+x)dx+xydy=0 x 0 is,